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The Fundamental Theorem of Calculus

The Fundamental Theorem of Calculus bridges differentiation and integration, two core concepts in calculus. It consists of two parts: the first establishes that the derivative of an integral function is the original function, while the second allows for the evaluation of definite integrals using antiderivatives. This theorem is crucial for calculating areas, volumes, and other quantities in various fields.

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1

FTC Part 1: g(x) = ∫ from a to x of f(t) dt - Result?

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g(x) is continuous on [a, b] and differentiable on (a, b) with g'(x) = f(x).

2

FTC Part 2: Evaluation Theorem - Purpose?

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Calculates definite integral of f on [a, b] using F(b) - F(a), where F is any antiderivative of f.

3

FTC Part 2: Relationship between F(x) and f(x)?

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F(x) is an antiderivative of f(x), meaning F'(x) = f(x).

4

FTC Implication: Area under curve f(x) - How to compute?

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Use FTC Part 2: Compute area from a to b as F(b) - F(a) with F being an antiderivative of f.

5

The ______ of the function F(x), which is the integral of f from a to x, is the original function f(x).

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derivative

6

Integration and differentiation are ______ operations, as shown by the relationship between F(x) and f(x).

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inverse

7

FTC Part 2: Relationship between antiderivative and definite integral

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FTC Part 2 states that the definite integral of f from a to b equals F(b) - F(a), where F is any antiderivative of f.

8

Antiderivative F of f: Expression involving constant C

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Any antiderivative F of f can be expressed as F(x) = g(x) + C, where g(x) is the integral of f from a to x and C is a constant.

9

Proof of FTC Part 2: Role of function g(x)

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The proof of FTC Part 2 uses g(x) = ∫ from a to x of f(t) dt to show that F(x) = g(x) + C, leading to the result F(b) - F(a).

10

The ______ is crucial for accurately computing integrals, vital for calculating areas, volumes, and other quantities expressible as integrals.

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FTC

11

The FTC helps in finding the ______ of an object, which is the average position of its mass, even for items with intricate shapes and diverse density.

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center of mass

12

FTC Part 1: Derivative of integral with variable upper limit

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Differentiate integral with variable upper limit by replacing the upper limit with the variable, e.g., d/dx ∫ from 1 to x of f(t) dt equals f(x).

13

FTC and Chain Rule: Derivative of integral with variable upper limit function

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Apply Chain Rule when upper limit is a function, e.g., d/dx ∫ from 1 to h(x) of f(t) dt equals f(h(x))·h'(x).

14

FTC Part 2: Evaluating definite integrals

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Compute area under curve using antiderivative at bounds, e.g., ∫ from a to b of f(x) dx equals F(b) - F(a), where F is the antiderivative of f.

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Understanding the Fundamental Theorem of Calculus

The Fundamental Theorem of Calculus (FTC) serves as a pivotal link between the processes of differentiation and integration, two of the main operations in calculus. This theorem is divided into two parts, each highlighting a unique aspect of their interplay. The first part of the FTC establishes that if a function f is continuous on a closed interval [a, b], then the function g, defined by the integral of f from a to x (g(x) = ∫ from a to x of f(t) dt), is not only continuous on [a, b] but also differentiable on the open interval (a, b), with its derivative g'(x) being equal to f(x). This part confirms that differentiation can reverse the process of integration. The second part, often referred to as the "evaluation theorem," provides a method for calculating the definite integral of a continuous function. It states that if F is any antiderivative of a continuous function f on [a, b], then the integral of f from a to b is given by F(b) - F(a), allowing for the computation of the area under the curve of f between a and b.
Close-up view of a hand in a white lab coat holding a glass flask with a blue gradient liquid against a black chalkboard background.

The Derivative of the Integral Function

Exploring the first part of the FTC further, consider a continuous function f on a closed interval [a, b]. We define a new function F(x) as the integral of f from a to x. This function F is continuous on [a, b] and differentiable on (a, b). The essence of the theorem is demonstrated by showing that the derivative of F(x) is the original function f(x). This is established by examining the limit of the difference quotient of F as h approaches zero and employing the Mean Value Theorem for Integrals. The conclusion is that the process of integration, represented by the function F, can be reversed by taking its derivative, which yields the original function f(x). This result is significant as it solidifies the concept that integration and differentiation are inverse operations.

Evaluating Definite Integrals Using Antiderivatives

The second part of the FTC greatly facilitates the evaluation of the area under a curve for a continuous function f on a closed interval [a, b]. If an antiderivative F of f is known, the definite integral of f from a to b can be efficiently calculated by the difference F(b) - F(a). This theorem is invaluable in practice, as it bypasses the need for more intricate geometric or numerical approaches. The proof involves the function g(x) = ∫ from a to x of f(t) dt and the realization that any antiderivative F of f can be written as F(x) = g(x) + C, where C is a constant. Evaluating g at the endpoints a and b and using the properties of antiderivatives leads to the straightforward result that the integral of f from a to b is F(b) - F(a).

Practical Applications of the Fundamental Theorem of Calculus

The FTC is not only theoretically significant but also has extensive practical applications across various scientific and engineering disciplines. It is instrumental in the precise calculation of integrals, which are essential in determining areas, volumes, and other physical quantities that can be expressed as integrals. For example, the FTC is used to calculate the center of mass of an object, analogous to finding the balance point when standing on one leg. The center of mass is the point that represents the average location of the mass in a body, and the FTC aids in determining this point for objects with complex shapes and varying density distributions.

Examples Illustrating the Fundamental Theorem of Calculus

To demonstrate the FTC in action, consider several examples. Applying the first part of the FTC, we can differentiate a function defined by an integral with a variable upper limit. For instance, the derivative of g(x) = ∫ from 1 to x of (1/t^2 + 1) dt is simply 1/(x^2 + 1). In cases where the Chain Rule is required, such as for g(x) = ∫ from 1 to x^2 of cos(r) dr, the derivative is 2x·cos(x^2). When both limits of integration are functions of a variable, as in g(t) = ∫ from t to t^3 of s^4 ds, the integral is evaluated by applying the FTC to each part separately. Using the second part of the FTC, we can directly evaluate definite integrals, such as calculating the area under the curve of 4 - x^2 from 0 to 2, which results in 16/3. These examples showcase the FTC's utility in a wide array of integration problems.