Hofmann Elimination is a fundamental organic chemistry reaction that produces the least substituted alkene from an amine precursor. Named after August Wilhelm Hofmann, this reaction is notable for its deviation from Zaitsev's rule, which typically predicts the formation of the most substituted alkene. The process involves the treatment of a tertiary amine with an alkylating agent to form a quaternary ammonium salt, followed by the abstraction of a β-hydrogen using a strong base, resulting in alkene formation. Its applications are widespread in both laboratory research and industrial processes, including the synthesis of polymers and pharmaceutical intermediates.
See moreWant to create maps from your material?
Insert your material in few seconds you will have your Algor Card with maps, summaries, flashcards and quizzes.
Try Algor
Click on each Card to learn more about the topic
1
Hofmann Elimination precursor molecule
Click to check the answer
2
Hofmann Elimination base requirement
Click to check the answer
3
Hofmann Elimination reaction mechanism
Click to check the answer
4
The reaction of ______ with methyl iodide leads to the formation of tetramethylammonium iodide, a precursor in Hofmann Elimination.
Click to check the answer
5
When tert-amyl chloride is combined with ______, the resulting compound can be treated with a strong base to produce isobutene.
Click to check the answer
6
Discoverer of Hofmann Elimination
Click to check the answer
7
Hofmann's contributions beyond elimination reactions
Click to check the answer
8
Institution established by Hofmann
Click to check the answer
9
The ______ production of alkenes such as propene and butene, often involves the use of ______ Elimination.
Click to check the answer
10
Hofmann Elimination mechanism
Click to check the answer
11
Hofmann Degradation reactant and product
Click to check the answer
12
Hofmann Elimination substrate
Click to check the answer
13
The outcome of β-elimination reactions, such as ______ or ______ Elimination, is influenced by the base's size and the reaction's stability.
Click to check the answer