Gravitational Force and Acceleration Due to Gravity

Understanding gravitational force is key to comprehending weight and the acceleration due to gravity (g). This force is what we feel as weight, calculated by the formula F = m * g. The value of g changes with altitude and geographical location, affecting an object's weight. The text explores how g varies with altitude above and below Earth's surface, its maximum at the surface, and its decrease with depth and distance.

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Understanding Gravitational Force and Weight

Gravitational force is the force of attraction that the Earth exerts on any object with mass, pulling it toward the planet's center. This force is what we commonly refer to as weight. According to Newton's second law of motion, force is the product of mass (m) and acceleration (a), given by the formula F = m * a. In the context of weight, the acceleration due to gravity (g) replaces a, leading to the equation F = m * g, which defines the weight (W) of an object. Weight is measured in Newtons (N), which are equivalent to kg * m/s². The value of g varies slightly depending on geographical location, being slightly less at the equator than at the poles, and decreases with altitude, making an object's weight slightly less at higher elevations.
Newton's cradle with one steel ball suspended at peak height, poised to strike stationary balls against a white background, showcasing momentum conservation.

Acceleration Due to Gravity on Earth's Surface

The acceleration due to gravity (g) is approximately constant near the Earth's surface but decreases with increasing altitude. This acceleration is the rate at which the velocity of an object increases as it falls freely under the influence of Earth's gravity. It is inversely proportional to the square of the distance (r) from the Earth's center, as described by the equation g ∝ 1/r². The value of g is also directly proportional to the mass (M) of the Earth, leading to the relationship g ∝ M. When the mass of the object (m) is much smaller than M (m << M), the combined proportionality becomes g ∝ M/r². By incorporating the universal gravitational constant (G), we arrive at the equation g = GM/r², which calculates the acceleration due to gravity, with G having a value of approximately 6.674 * 10⁻¹¹ Nm²/kg².

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1

Gravitational force definition

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Attraction force Earth exerts on objects with mass towards its center.

2

Newton's second law formula

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Force equals mass times acceleration (F = m * a).

3

Weight measurement unit

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Weight measured in Newtons (N), equivalent to kg * m/s².

4

The rate at which an object's velocity increases when falling freely is known as the ______ due to gravity.

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acceleration

5

The formula for calculating the acceleration due to gravity is g = ______ divided by the square of the distance from the Earth's center, where G is the universal gravitational constant.

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GM/r²

6

Equation for gravity at altitude (h)

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g = GM/(R + h)², where g is gravity, G is the gravitational constant, M is Earth's mass, R is Earth's radius, and h is altitude.

7

Relationship between g and altitude

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As altitude (h) increases, gravitational strength (g) decreases due to the increase in distance from Earth's center.

8

Gravitational pull on satellites in orbit

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Satellites experience less gravitational pull than surface objects due to being at a higher altitude, where Earth's gravity is weaker.

9

The formula for the mass (m) influencing gravity inside the Earth is m = (4/3)πr³ρ, where ρ represents the ______ ______ of the Earth.

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average density

10

Gravity variation within Earth

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Linear increase in g with r, max at Earth's surface.

11

Gravity variation beyond Earth's surface

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Decreases in a parabolic manner for r > Earth's radius (R).

12

Calculating weight in orbit

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Use mass and orbital g value to determine weight in orbit.

13

In physics and engineering, it's essential to understand that gravity's pull becomes ______ at the Earth's ______ and negligible at great distances away.

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zero center

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